计算取值(JTJ041-2000公路桥涵施工技术规范附录G-8及设计规定)
k=0.0015 ??=0.225 取平均值
Eg=1.95?105MPa Ay=140?3=420mm2 Ay=140?4=560mm2 控制应力P=585.9?103 N
控制应力P=781.2?103 N
将20m梁板的1/2段预应力筋分为4段计算伸长值
计算N1束
① 计算直线段AB段伸长值
L=65cm P=585.9?103 N
??L1=P*L/Eg* Ay=585.9?103?65/1.95?105?420=4.65㎜
② 计算直线段BC段伸长值
L=34.2cm P=585.9?103 N ??=0
e-(kl+????)=0.999487
终点力 Ps=P?e-(kl+????)= 585.9?103?0.999487= 585.599?103 N
P=(P+ Ps)/2=(585.9?103 +585.599?103 )/2=585.75?103 N
??L2=P*L/Eg* Ay=585.75?103?34.2/1.95?105?420=2.45㎜
③ 计算曲线段CD段伸长值
L=439.8cm P=585.599?103 N ??=12o???/180=0.2093(rad)
e-(kl+????)=0.947727
Ps=P?e-(kl+????)= 585.599?103?0.947727= 554.988?103 N
P=(P+ Ps)/2=(585.599?103 +554.988?103 )/2=570.294?103 N
??L3=P*L/Eg* Ay=570.294?103?439.8/1.95?105?420=30.62㎜
④ 计算直线段DE段伸长值
L=5.079m P=554.988?103 N ??=0
e-(kl+????)=0.9924104
Ps=P?e-(kl+????)= 554.988?103 ?0.9924104=550.776?103 N
P=(P+ Ps)/2=(554.988?103 +550.776?103 )/2=552.882?103 N
??L4=P*L/Eg* Ay=552.882?103?5.079/1.95?105?420=34.29㎜
N1束伸长值??L=2?(??L1+??L2+??L3+??L4)=144.0㎜
计算N2束
① 计算直线段AB段伸长值
L=65cm P=585.9?103 N
??L1=P*L/Eg* Ay=585.9?103?65/1.95?105?420=4.65㎜
② 计算直线段BC段伸长值
L=58.7cm P=585.9?103 N ??=0
e-(kl+????)=0.99912
Ps=P?e-(kl+????)= 585.9?103?0.99912= 585.384?103 N
P=(P+ Ps)/2=(585.9?103 +585.384?103 )/2=585.642?103 N
??L2=P*L/Eg* Ay=585.642?103?58.7/1.95?105?420=4.20㎜
③ 计算曲线段CD段伸长值
L=293.2cm P=585.384?103 N ??=8o???/180=0.1396(rad)
e-(kl+????)=0.964826
Ps=P?e-(kl+????)= 585.384?103?0.964826= 564.794?103 N
P=(P+ Ps)/2=(585.384?103 +564.794?103 )/2=575.089?103 N
??L3=P*L/Eg* Ay=575.089?103?293.2/1.95?105?420=20.59㎜
④ 计算直线段DE段伸长值
L=6.276m P=564.794?103 N ??=0
e-(kl+????)=0.990630
Ps=P?e-(kl+????)= 564.794?103 ?0.990630=559.502?103 N
P=(P+ Ps)/2=(564.794?103 +559.502?103 )/2=562.148?103 N
??L4=P*L/Eg* Ay=562.148?103?6.276/1.95?105?420=43.08㎜
N2束伸长值??L=2?(??L1+??L2+??L3+??L4)=145.0㎜
计算N3束
①计算直线段AB段伸长值
L=65cm P=781.2?103 N
??L1=P*L/Eg* Ay=781.2?103?65/1.95?105?560=4.65㎜
②计算直线段BC段伸长值
L=76.7cm P=781.2?103 N ??=0
e-(kl+????)=0.99885
Ps=P?e-(kl+????)= 781.2?103?0.99885= 780.302?103 N
P=(P+ Ps)/2=(781.2?103 +780.302?103 )/2=780.751?103 N
??L2=P*L/Eg* Ay=780.751?103?76.7/1.95?105?560=5.48㎜
③ 计算曲线段CD段伸长值
L=87.3cm P=780.302?103 N ??=2o???/180=0.0349(rad)
e-(kl+????)=0.99088
Ps=P?e-(kl+????)= 780.302?103?0.99088= 773.186?103 N
P=(P+ Ps)/2=(780.302?103 +773.186?103 )/2=776.744?103 N
??L3=P*L/Eg* Ay=776.744?103?87.3/1.95?105?560=6.21㎜
④ 计算直线段DE段伸长值
L=814.1cm P=773.186?103 N ??=0
e-(kl+????)=0.987863
Ps=P?e-(kl+????)= 773.186?103 ?0.987863=763.802?103 N
P=(P+ Ps)/2=(773.186?103 +763.802?103 )/2=768.494?103 N
??L4=P*L/Eg* Ay=768.494?103?814.1/1.95?105?560=57.29㎜